簡(jiǎn)單的2048小游戲
不多說,直接上圖,這里并未實(shí)現(xiàn)GUI之類的,需要的話,可自行實(shí)現(xiàn):
接下來就是代碼模塊,其中的2048游戲原來網(wǎng)絡(luò)上有很多,我就不詳細(xì)寫上去了,都寫在注釋里面了。唯一要注意的就是需要先去了解一下矩陣的轉(zhuǎn)置,這里會(huì)用到
import random board = [[0, 0, 0, 0], [0, 0, 0, 0], [0, 0, 0, 0], [0, 0, 0, 0]] # 打印游戲界面 def display(board, score): print('{0:4} {1:4} {2:4} {3:4}'.format(board[0][0], board[0][1], board[0][2], board[0][3])) print('{0:4} {1:4} {2:4} {3:4}'.format(board[1][0], board[1][1], board[1][2], board[1][3])) print('{0:4} {1:4} {2:4} {3:4}'.format(board[2][0], board[2][1], board[2][2], board[2][3])) print('{0:4} {1:4} {2:4} {3:4}'.format(board[3][0], board[3][1], board[3][2], board[3][3]), ' 分?jǐn)?shù):', score) # 初始化游戲,在4*4里面隨機(jī)生成兩個(gè)2 def init(board): # 游戲先都重置為0 for i in range(4): for j in range(4): board[i][j] = 0 # 隨機(jī)生成兩個(gè)2保存的位置 randomposition = random.sample(range(0, 15), 2) board[int(randomposition[0] / 4)][randomposition[0] % 4] = 2 board[int(randomposition[1] / 4)][randomposition[1] % 4] = 2 def addSameNumber(boardList, direction): '''需要在列表中查找相鄰相同的數(shù)字相加,返回增加的分?jǐn)?shù) :param boardList: 經(jīng)過對(duì)齊非零的數(shù)字處理過后的二維數(shù)組 :param direction: direction == 'left'從右向左查找,找到相同且相鄰的兩個(gè)數(shù)字,左側(cè)數(shù)字翻倍,右側(cè)數(shù)字置0 direction == 'right'從左向右查找,找到相同且相鄰的兩個(gè)數(shù)字,右側(cè)數(shù)字翻倍,左側(cè)數(shù)字置0 :return: ''' addNumber = 0 # 向左以及向上的操作 if direction == 'left': for i in [0, 1, 2]: if boardList[i] == boardList[i+1] != 0: boardList[i] *= 2 boardList[i + 1] = 0 addNumber += boardList[i] return {'continueRun': True, 'addNumber': addNumber} return {'continueRun': False, 'addNumber': addNumber} # 向右以及向下的操作 else: for i in [3, 2, 1]: if boardList[i] == boardList[i-1] != 0: boardList[i] *= 2 boardList[i - 1] = 0 addNumber += boardList[i] return {'continueRun': True, 'addNumber': addNumber} return {'continueRun': False, 'addNumber': addNumber} def align(boardList, direction): '''對(duì)齊非零的數(shù)字 direction == 'left':向左對(duì)齊,例如[8,0,0,2]左對(duì)齊后[8,2,0,0] direction == 'right':向右對(duì)齊,例如[8,0,0,2]右對(duì)齊后[0,0,8,2] ''' # 先移除列表里面的0,如[8,0,0,2]->[8,2],1.先找0的個(gè)數(shù),然后依照個(gè)數(shù)進(jìn)行清理 # boardList.remove(0):移除列表中的某個(gè)值的第一個(gè)匹配項(xiàng),所以[8,0,0,2]會(huì)移除兩次0 for x in range(boardList.count(0)): boardList.remove(0) # 移除的0重新補(bǔ)充回去,[8,2]->[8,2,0,0] if direction == 'left': boardList.extend([0 for x in range(4 - len(boardList))]) else: boardList[:0] = [0 for x in range(4 - len(boardList))] def handle(boardList, direction): ''' 處理一行(列)中的數(shù)據(jù),得到最終的該行(列)的數(shù)字狀態(tài)值, 返回得分 :param boardList: 列表結(jié)構(gòu),存儲(chǔ)了一行(列)中的數(shù)據(jù) :param direction: 移動(dòng)方向,向上和向左都使用方向'left',向右和向下都使用'right' :return: 返回一行(列)處理后加的分?jǐn)?shù) ''' addscore = 0 # 先處理數(shù)據(jù),把數(shù)據(jù)都往指定方向進(jìn)行運(yùn)動(dòng) align(boardList, direction) result = addSameNumber(boardList, direction) # 當(dāng)result['continueRun'] 為True,代表需要再次執(zhí)行 while result['continueRun']: # 重新對(duì)其,然后重新執(zhí)行合并,直到再也無法合并為止 addscore += result['addNumber'] align(boardList, direction) result = addSameNumber(boardList, direction) # 直到執(zhí)行完畢,及一行的數(shù)據(jù)都不存在相同的 return {'addscore': addscore} # 游戲操作函數(shù),根據(jù)移動(dòng)方向重新計(jì)算矩陣狀態(tài)值,并記錄得分 def operator(board): # 每一次的操作所加的分?jǐn)?shù),以及操作后游戲是否觸發(fā)結(jié)束狀態(tài)(即數(shù)據(jù)占滿位置) addScore = 0 gameOver = False # 默認(rèn)向左 direction = 'left' op = input("請(qǐng)輸入您的操作:") if op in ['a', 'A']: # 方向向左 direction = 'left' # 一行一行進(jìn)行處理 for row in range(4): addScore += handle(board[row], direction)['addscore'] elif op in ['d', 'D']: direction = 'right' for row in range(4): addScore += handle(board[row], direction)['addscore'] elif op in ['w', 'W']: # 向上相當(dāng)于向左的轉(zhuǎn)置處理 direction = 'left' board = list(map(list, zip(*board))) # 一行一行進(jìn)行處理 for row in range(4): addScore += handle(board[row], direction)['addscore'] board = list(map(list, zip(*board))) elif op in ['s', 'S']: # 向下相當(dāng)于向右的轉(zhuǎn)置處理 direction = 'right' board = list(map(list, zip(*board))) # 一行一行進(jìn)行處理 for row in range(4): addScore += handle(board[row], direction)['addscore'] board = list(map(list, zip(*board))) else: print("錯(cuò)誤輸入!請(qǐng)輸入[W, S, A, D]或者對(duì)應(yīng)小寫") return {'gameOver': gameOver, 'addScore': addScore, 'board': board} # 每一次操作后都需要判斷0的數(shù)量,如果滿了,則游戲結(jié)束 number_0 = 0 for q in board: # count(0)是指0出現(xiàn)的個(gè)數(shù),是掃描每一行的 number_0 += q.count(0) # 如果number_0為0,說明滿了 if number_0 == 0: gameOver = True return {'gameOver': gameOver, 'addScore': addScore, 'board': board} # 說明還沒有滿,則在空的位置上加上一個(gè)2或者4,概率為3:1 else: addnum = random.choice([2,2,2,4]) position_0_list = [] # 找出0的位置,并保存起來 for i in range(4): for j in range(4): if board[i][j] == 0: position_0_list.append(i*4 + j) # 在剛才記錄的0的位置里面隨便找一個(gè),然后替換成生成的2或者4 randomposition = random.sample(position_0_list, 1) board[int(randomposition[0] / 4)][randomposition[0] % 4] = addnum return {'gameOver': gameOver, 'addScore': addScore, 'board': board} if __name__ == '__main__': print('輸入:W(上) S(下) A(左) D(右).') # 初始化游戲界面,游戲分?jǐn)?shù) gameOver = False init(board) score = 0 # 游戲未結(jié)束,則一直運(yùn)行 while gameOver != True: display(board, score) operator_result = operator(board) board = operator_result['board'] if operator_result['gameOver'] == True: print("游戲結(jié)束,你輸了!") print("你的最終得分:", score) gameOver = operator_result['gameOver'] break else: # 加上這一步的分 score += operator_result['addScore'] if score >= 2048: print("牛啊牛啊,你吊竟然贏了!") print("你的最終得分:", score) # 結(jié)束游戲 gameOver = True break
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標(biāo)簽:宿遷 蘭州 六盤水 駐馬店 山東 常州 江蘇 成都
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