變量由作用范圍限制
分類:按照作用域分類
變量的作用范圍
LEGB原則
# 認為a1是全局的 a1 = 100 def fun(): print(a1) print("I am in fun") # a2的作用范圍是fun a2 = 99 print(a2) print(a1) fun() # print(a2)
100
100
I am in fun
99
使用global
案例如下
def fun(): global b1 b1 = 100 print(b1) print("I am in fun") b2 = 99 print(b2) fun() print(b1)
100
I am in fun
99
100
可以通過globals和locals顯示出局部變量和全局變量
參考一下案例
# globals 和 locals # globals 和 locals 叫做內(nèi)建函數(shù) a = 1 b = 2 def fun(c,d): e = 111 print("Locals={0}".format(locals())) print("Globals={0}".format(globals())) fun(100, 200)
Locals={'c': 100, 'd': 200, 'e': 111}
Globals={'__name__': '__main__', '__doc__': 'Automatically created module for IPython interactive environment', '__package__': None, '__loader__': None, '__spec__': None, '__builtin__': module 'builtins' (built-in)>, '__builtins__': module 'builtins' (built-in)>, '_ih': ['', '# 認為a1是全局的\na1 = 100\n\ndef fun():\n print(a1)\n print("I am in fun")\n a2 = 99\n print(a2)\n \nprint(a2)', '# 認為a1是全局的\na1 = 100\n\ndef fun():\n print(a1)\n print("I am in fun")\n a2 = 99\n print(a2)\n \nprint(a1)', '# 認為a1是全局的\na1 = 100\n\ndef fun():\n print(a1)\n print("I am in fun")\n a2 = 99\n print(a2)\n \nprint(a1)\nfun()\n# print(a2)', '# 認為a1是全局的\na1 = 100\n\ndef fun():\n print(a1)\n print("I am in fun")\n a2 = 99\n print(a2)\n \nprint(a1)\nfun()\nprint(a2)', '# 認為a1是全局的\na1 = 100\n\ndef fun():\n print(a1)\n print("I am in fun")\n a2 = 99\n print(a2)\n \nprint(a1)\nfun()\n# print(a2)', 'def fun():\n b1 = 100\n print(b1)\n print("I am in fun")\n b2 = 99\n print(b2)\n \nfun()', 'def fun():\n global b1 = 100\n print(b1)\n print("I am in fun")\n b2 = 99\n print(b2)\n\nprint(b1)', 'def fun():\n global b1 \n b1 = 100\n print(b1)\n print("I am in fun")\n b2 = 99\n print(b2)\n\nprint(b1)', 'def fun():\n global b1 \n b1 = 100\n print(b1)\n print("I am in fun")\n b2 = 99\n print(b2)\n\nprint(b1)', 'def fun():\n global b1 \n b1 = 100\n print(b1)\n print("I am in fun")\n b2 = 99\n print(b2)\n\nprint(b1)', '# globals 和 locals\na = 1\nb = 2\n\ndef fun(c,d):\n e = 111\n print("Locals={0}".format(locals()))\n print("Globals={0}".format(globals())\n \nfun(100, 200)', '# globals 和 locals\na = 1\nb = 2\n\ndef fun(c,d):\n e = 111\n print("Locals={0}".format(locals()))\n print("Globals={0}".format(globals()))\n \nfun(100, 200)', '# globals 和 locals\n# globals 和 locals 叫做內(nèi)建函數(shù)\na = 1\nb = 2\n\ndef fun(c,d):\n e = 111\n print("Locals={0}".format(locals()))\n print("Globals={0}".format(globals()))\n \nfun(100, 200)'], '_oh': {}, '_dh': ['d:\\Jupyter\\nootbook\\筆記'], 'In': ['', '# 認為a1是全局的\na1 = 100\n\ndef fun():\n print(a1)\n print("I am in fun")\n a2 = 99\n print(a2)\n \nprint(a2)', '# 認為a1是全局的\na1 = 100\n\ndef fun():\n print(a1)\n print("I am in fun")\n a2 = 99\n print(a2)\n \nprint(a1)', '# 認為a1是全局的\na1 = 100\n\ndef fun():\n print(a1)\n print("I am in fun")\n a2 = 99\n print(a2)\n \nprint(a1)\nfun()\n# print(a2)', '# 認為a1是全局的\na1 = 100\n\ndef fun():\n print(a1)\n print("I am in fun")\n a2 = 99\n print(a2)\n \nprint(a1)\nfun()\nprint(a2)', '# 認為a1是全局的\na1 = 100\n\ndef fun():\n print(a1)\n print("I am in fun")\n a2 = 99\n print(a2)\n \nprint(a1)\nfun()\n# print(a2)', 'def fun():\n b1 = 100\n print(b1)\n print("I am in fun")\n b2 = 99\n print(b2)\n \nfun()', 'def fun():\n global b1 = 100\n print(b1)\n print("I am in fun")\n b2 = 99\n print(b2)\n\nprint(b1)', 'def fun():\n global b1 \n b1 = 100\n print(b1)\n print("I am in fun")\n b2 = 99\n print(b2)\n\nprint(b1)', 'def fun():\n global b1 \n b1 = 100\n print(b1)\n print("I am in fun")\n b2 = 99\n print(b2)\n\nprint(b1)', 'def fun():\n global b1 \n b1 = 100\n print(b1)\n print("I am in fun")\n b2 = 99\n print(b2)\n\nprint(b1)', '# globals 和 locals\na = 1\nb = 2\n\ndef fun(c,d):\n e = 111\n print("Locals={0}".format(locals()))\n print("Globals={0}".format(globals())\n \nfun(100, 200)', '# globals 和 locals\na = 1\nb = 2\n\ndef fun(c,d):\n e = 111\n print("Locals={0}".format(locals()))\n print("Globals={0}".format(globals()))\n \nfun(100, 200)', '# globals 和 locals\n# globals 和 locals 叫做內(nèi)建函數(shù)\na = 1\nb = 2\n\ndef fun(c,d):\n e = 111\n print("Locals={0}".format(locals()))\n print("Globals={0}".format(globals()))\n \nfun(100, 200)'], 'Out': {}, 'get_ipython': bound method InteractiveShell.get_ipython of ipykernel.zmqshell.ZMQInteractiveShell object at 0x000001B07AF18BA8>>, 'exit': IPython.core.autocall.ZMQExitAutocall object at 0x000001B07D7398D0>, 'quit': IPython.core.autocall.ZMQExitAutocall object at 0x000001B07D7398D0>, '_': '', '__': '', '___': '', '_i': '# globals 和 locals\na = 1\nb = 2\n\ndef fun(c,d):\n e = 111\n print("Locals={0}".format(locals()))\n print("Globals={0}".format(globals()))\n \nfun(100, 200)', '_ii': '# globals 和 locals\na = 1\nb = 2\n\ndef fun(c,d):\n e = 111\n print("Locals={0}".format(locals()))\n print("Globals={0}".format(globals())\n \nfun(100, 200)', '_iii': 'def fun():\n global b1 \n b1 = 100\n print(b1)\n print("I am in fun")\n b2 = 99\n print(b2)\n\nprint(b1)', '_i1': '# 認為a1是全局的\na1 = 100\n\ndef fun():\n print(a1)\n print("I am in fun")\n a2 = 99\n print(a2)\n \nprint(a2)', 'a1': 100, 'fun': function fun at 0x000001B07D8C41E0>, '_i2': '# 認為a1是全局的\na1 = 100\n\ndef fun():\n print(a1)\n print("I am in fun")\n a2 = 99\n print(a2)\n \nprint(a1)', '_i3': '# 認為a1是全局的\na1 = 100\n\ndef fun():\n print(a1)\n print("I am in fun")\n a2 = 99\n print(a2)\n \nprint(a1)\nfun()\n# print(a2)', '_i4': '# 認為a1是全局的\na1 = 100\n\ndef fun():\n print(a1)\n print("I am in fun")\n a2 = 99\n print(a2)\n \nprint(a1)\nfun()\nprint(a2)', '_i5': '# 認為a1是全局的\na1 = 100\n\ndef fun():\n print(a1)\n print("I am in fun")\n a2 = 99\n print(a2)\n \nprint(a1)\nfun()\n# print(a2)', '_i6': 'def fun():\n b1 = 100\n print(b1)\n print("I am in fun")\n b2 = 99\n print(b2)\n \nfun()', '_i7': 'def fun():\n global b1 = 100\n print(b1)\n print("I am in fun")\n b2 = 99\n print(b2)\n\nprint(b1)', '_i8': 'def fun():\n global b1 \n b1 = 100\n print(b1)\n print("I am in fun")\n b2 = 99\n print(b2)\n\nprint(b1)', '_i9': 'def fun():\n global b1 \n b1 = 100\n print(b1)\n print("I am in fun")\n b2 = 99\n print(b2)\n\nprint(b1)', '_i10': 'def fun():\n global b1 \n b1 = 100\n print(b1)\n print("I am in fun")\n b2 = 99\n print(b2)\n\nprint(b1)', '_i11': '# globals 和 locals\na = 1\nb = 2\n\ndef fun(c,d):\n e = 111\n print("Locals={0}".format(locals()))\n print("Globals={0}".format(globals())\n \nfun(100, 200)', '_i12': '# globals 和 locals\na = 1\nb = 2\n\ndef fun(c,d):\n e = 111\n print("Locals={0}".format(locals()))\n print("Globals={0}".format(globals()))\n \nfun(100, 200)', 'a': 1, 'b': 2, '_i13': '# globals 和 locals\n# globals 和 locals 叫做內(nèi)建函數(shù)\na = 1\nb = 2\n\ndef fun(c,d):\n e = 111\n print("Locals={0}".format(locals()))\n print("Globals={0}".format(globals()))\n \nfun(100, 200)'}
把一個字符串當成一個表達式來執(zhí)行,返回表達式執(zhí)行后的結(jié)果
語法:
eval(string_code, globals=None, locals=None)
跟eval功能類似,但是,不返回結(jié)果
語法:
exec(string_code, globals=None, locals=None)
x = 100 y = 200 # 執(zhí)行x+y # z = x + y z1 = x + y z2 = eval("x+y") print(z1) print(z2)
300
300
# exec案例 x = 100 y = 200 # 執(zhí)行x+y # z = x + y z1 = x + y # 1. 注意字符串中引號的寫法 # 2. 比對exec執(zhí)行結(jié)果和代碼執(zhí)行結(jié)果 z2 = exec("print('x+y:',x+y)") print(z1) print(z2)
x+y: 300
300
None
# 遞歸調(diào)用深度限制代碼 x = 0 def fun(): global x x += 1 print(x) # 函數(shù)自己調(diào)用自己 fun() # 調(diào)用函數(shù) # fun()
---------------------------------------------------------------------------
RecursionError Traceback (most recent call last)
ipython-input-23-bfedb7e396bc> in module>
10
11 # 調(diào)用函數(shù)
---> 12 fun()
ipython-input-23-bfedb7e396bc> in fun()
7 print(x)
8 # 函數(shù)自己調(diào)用自己
----> 9 fun()
10
11 # 調(diào)用函數(shù)
... last 1 frames repeated, from the frame below ...
ipython-input-23-bfedb7e396bc> in fun()
7 print(x)
8 # 函數(shù)自己調(diào)用自己
----> 9 fun()
10
11 # 調(diào)用函數(shù)
RecursionError: maximum recursion depth exceeded while calling a Python object
# 斐波那契數(shù)列 # 一列數(shù)字,第一個值是1,第二個也是1,從第三個開始,每一個數(shù)字的值等于前兩個數(shù)字出現(xiàn)的值的和 # 數(shù)學公式為: f(1) = 1, f(2) = 1, f(n) = f(n - 1) + f(n - 2) # 例如: 1,1,2,3,5,8,13.... # n表示求第n個數(shù)字的斐波那契數(shù)列的值 def fib(n): if n == 1 or n == 2: return 1 elif n > 0: return fib(n-1) + fib(n-2) else: return None print(fib(3)) print(fib(5)) print(fib(10)) print(fib(-1)) print(fib(1))
2
5
55
None
1
內(nèi)置數(shù)據(jù)結(jié)構(gòu)(變量類型)
一組有順序的數(shù)據(jù)的組合
創(chuàng)建列表
# 1. 創(chuàng)建空列表 l1 = [] # type是內(nèi)置函數(shù),負責打印出變量的類型 print(type(l1)) print(l1) # 2. 創(chuàng)建帶值的列表 l2 = [100] print(type(l2)) print(l2) # 3. 創(chuàng)建列表,帶多個值 l3 = [2,3,5,5,9,7,8,] print(type(l3)) print(l3) # 4. 使用list() l4 = list() print(type(l4)) print(l4)
class 'list'>
[]
class 'list'>
[100]
class 'list'>
[2, 3, 5, 5, 9, 7, 8]
class 'list'>
[]
訪問
分片操作
# 下標訪問列表 l = [3,2,5,1,9,8,7] print(l[1])
2
print(l[0])
3
# 分片操作 # 注意截取的范圍,包含左邊的下標值,不包含右邊的下標值 print(l[1:4]) # 下標值可以為空,如果不寫,左邊下標值默認為0,右邊下標值為最大數(shù)加一,即表示截取到最后一個數(shù)據(jù) print(l[:]) print(l[:4]) print(l[2:])
[2, 5, 1]
[3, 2, 5, 1, 9, 8, 7]
[3, 2, 5, 1]
[5, 1, 9, 8, 7]
print(l) # 分片可以控制增長幅度,默認增長幅度為1 print(l[1:6:1]) # 打印從下標1開始的數(shù)字,每次隔一個 print(l[1:6:2]) # 下標可以超出范圍,超出后不在考慮多余下標內(nèi)容 print(l[2:10]) # 下標值,增長幅度可以為負數(shù) # 為負數(shù),表明為從右往左 # 規(guī)定: 數(shù)組最后一個數(shù)字的下標是-1
[3, 2, 5, 1, 9, 8, 7]
[2, 5, 1, 9, 8]
[2, 1, 8]
[5, 1, 9, 8, 7]
# 分片之負數(shù)下標 print(l) # 下面顯示的是為空,因為默認分片總是從左向右截取 print(l[-2:-4]) print(l[-4:-2]) # 如果分片一定左邊值比右邊大,則步長參數(shù)需要使用負數(shù) # 此案例為一個list直接正反截取提供了一個思路 print(l[-2:-4:-1]) print(l[-1:-8:-1])
[3, 2, 5, 1, 9, 8, 7]
[]
[1, 9]
[8, 9]
[7, 8, 9, 1, 5, 2, 3]
內(nèi)置函數(shù)id,負責顯示一個變量或者數(shù)據(jù)的唯一確定編號
# id函數(shù)舉例 a = 100 b = 200 print(id(a)) print(id(b)) # a跟c指向同一份數(shù)據(jù) c = a print(id(c)) a = 101 print(a) print(c) print(id(a)) print(id(c))
140734817148832
140734817152032
140734817148832
101
100
140734817148864
140734817148832
# 通過id可以直接判斷出分片是重新生成了一份數(shù)據(jù)還是使用同一份數(shù)據(jù) l = [3,5,6,8,5,43,4,7] ll = l[:] # 分片操作 lll = ll # 如果兩個id值一樣,則表明分片產(chǎn)生的列表是使用的同一地址同一份數(shù)據(jù) # 否則,則表明分片是重新產(chǎn)生了一份數(shù)據(jù),即一個新的列表,然后把數(shù)據(jù)拷貝到新列表中 print(id(l)) print(id(ll)) print(id(lll)) # 通過id知道,ll和lll是同一份數(shù)據(jù),驗證代碼如下 l[1] = 100 print(l) print(ll) print(lll) ll[1] = 100 print(ll) print(lll)
1857540073800
1857540052488
1857540052488
[3, 100, 6, 8, 5, 43, 4, 7]
[3, 5, 6, 8, 5, 43, 4, 7]
[3, 5, 6, 8, 5, 43, 4, 7]
[3, 100, 6, 8, 5, 43, 4, 7]
[3, 100, 6, 8, 5, 43, 4, 7]
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標簽:石家莊 錫林郭勒盟 昆明 懷化 文山 梅州 西寧 浙江
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